5(3x-2)+2(3x-18)=40

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Solution for 5(3x-2)+2(3x-18)=40 equation: 



5(3x-2)+2(3x-18)=40

We move all terms to the left:

5(3x-2)+2(3x-18)-(40)=0

We multiply parentheses

15x+6x-10-36-40=0

We add all the numbers together, and all the variables

21x-86=0

We move all terms containing x to the left, all other terms to the right

21x=86

x=86/21

x=4+2/21

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