5(3x-2)+4(2x+1)=2(4x-1)

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Solution for 5(3x-2)+4(2x+1)=2(4x-1) equation: 



5(3x-2)+4(2x+1)=2(4x-1)

We move all terms to the left:

5(3x-2)+4(2x+1)-(2(4x-1))=0

We multiply parentheses

15x+8x-(2(4x-1))-10+4=0



We calculate terms in parentheses: -(2(4x-1)), so:

2(4x-1)

We multiply parentheses

8x-2

Back to the equation:

-(8x-2)



We add all the numbers together, and all the variables

23x-(8x-2)-6=0

We get rid of parentheses

23x-8x+2-6=0

We add all the numbers together, and all the variables

15x-4=0

We move all terms containing x to the left, all other terms to the right

15x=4

x=4/15

x=4/15

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