5(3x-2)+5=3(2x-1)+1

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Solution for 5(3x-2)+5=3(2x-1)+1 equation: 



5(3x-2)+5=3(2x-1)+1

We move all terms to the left:

5(3x-2)+5-(3(2x-1)+1)=0

We multiply parentheses

15x-(3(2x-1)+1)-10+5=0



We calculate terms in parentheses: -(3(2x-1)+1), so:

3(2x-1)+1

We multiply parentheses

6x-3+1

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

15x-(6x-2)-5=0

We get rid of parentheses

15x-6x+2-5=0

We add all the numbers together, and all the variables

9x-3=0

We move all terms containing x to the left, all other terms to the right

9x=3

x=3/9

x=1/3

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