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5(3x-2)-4(2x-3)=3(1-2x)
We move all terms to the left:
5(3x-2)-4(2x-3)-(3(1-2x))=0
We add all the numbers together, and all the variables
5(3x-2)-4(2x-3)-(3(-2x+1))=0
We multiply parentheses
15x-8x-(3(-2x+1))-10+12=0
We calculate terms in parentheses: -(3(-2x+1)), so:We add all the numbers together, and all the variables
3(-2x+1)
We multiply parentheses
-6x+3
Back to the equation:
-(-6x+3)
7x-(-6x+3)+2=0
We get rid of parentheses
7x+6x-3+2=0
We add all the numbers together, and all the variables
13x-1=0
We move all terms containing x to the left, all other terms to the right
13x=1
x=1/13
x=1/13
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