5(3x-2)=(2x+1)

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Solution for 5(3x-2)=(2x+1) equation: 



5(3x-2)=(2x+1)

We move all terms to the left:

5(3x-2)-((2x+1))=0

We multiply parentheses

15x-((2x+1))-10=0



We calculate terms in parentheses: -((2x+1)), so:

(2x+1)

We get rid of parentheses

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

15x-2x-1-10=0

We add all the numbers together, and all the variables

13x-11=0

We move all terms containing x to the left, all other terms to the right

13x=11

x=11/13

x=11/13

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