5(3x-2)=2(7x+3)

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Solution for 5(3x-2)=2(7x+3) equation: 



5(3x-2)=2(7x+3)

We move all terms to the left:

5(3x-2)-(2(7x+3))=0

We multiply parentheses

15x-(2(7x+3))-10=0



We calculate terms in parentheses: -(2(7x+3)), so:

2(7x+3)

We multiply parentheses

14x+6

Back to the equation:

-(14x+6)



We get rid of parentheses

15x-14x-6-10=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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