5(3x-2)=3(2x+1)+2x+1x

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Solution for 5(3x-2)=3(2x+1)+2x+1x equation: 



5(3x-2)=3(2x+1)+2x+1x

We move all terms to the left:

5(3x-2)-(3(2x+1)+2x+1x)=0

We multiply parentheses

15x-(3(2x+1)+2x+1x)-10=0



We calculate terms in parentheses: -(3(2x+1)+2x+1x), so:

3(2x+1)+2x+1x

We add all the numbers together, and all the variables

3x+3(2x+1)

We multiply parentheses

3x+6x+3

We add all the numbers together, and all the variables

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

15x-9x-3-10=0

We add all the numbers together, and all the variables

6x-13=0

We move all terms containing x to the left, all other terms to the right

6x=13

x=13/6

x=2+1/6

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