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5(3x-2)=4(x+15)
We move all terms to the left:
5(3x-2)-(4(x+15))=0
We multiply parentheses
15x-(4(x+15))-10=0
We calculate terms in parentheses: -(4(x+15)), so:We get rid of parentheses
4(x+15)
We multiply parentheses
4x+60
Back to the equation:
-(4x+60)
15x-4x-60-10=0
We add all the numbers together, and all the variables
11x-70=0
We move all terms containing x to the left, all other terms to the right
11x=70
x=70/11
x=6+4/11
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