5(3x-2)=6(3-x)

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Solution for 5(3x-2)=6(3-x) equation: 



5(3x-2)=6(3-x)

We move all terms to the left:

5(3x-2)-(6(3-x))=0

We add all the numbers together, and all the variables

5(3x-2)-(6(-1x+3))=0

We multiply parentheses

15x-(6(-1x+3))-10=0



We calculate terms in parentheses: -(6(-1x+3)), so:

6(-1x+3)

We multiply parentheses

-6x+18

Back to the equation:

-(-6x+18)



We get rid of parentheses

15x+6x-18-10=0

We add all the numbers together, and all the variables

21x-28=0

We move all terms containing x to the left, all other terms to the right

21x=28

x=28/21

x=1+1/3

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