5(3x-2)=6x-(x+2)+(-x+3)

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Solution for 5(3x-2)=6x-(x+2)+(-x+3) equation: 



5(3x-2)=6x-(x+2)+(-x+3)

We move all terms to the left:

5(3x-2)-(6x-(x+2)+(-x+3))=0

We add all the numbers together, and all the variables

5(3x-2)-(6x-(x+2)+(-1x+3))=0

We multiply parentheses

15x-(6x-(x+2)+(-1x+3))-10=0



We calculate terms in parentheses: -(6x-(x+2)+(-1x+3)), so:

6x-(x+2)+(-1x+3)

We get rid of parentheses

6x-x-1x-2+3

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We get rid of parentheses

15x-4x-1-10=0

We add all the numbers together, and all the variables

11x-11=0

We move all terms containing x to the left, all other terms to the right

11x=11

x=11/11

x=1

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