5(3x-2)=7(x-1)

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Solution for 5(3x-2)=7(x-1) equation: 



5(3x-2)=7(x-1)

We move all terms to the left:

5(3x-2)-(7(x-1))=0

We multiply parentheses

15x-(7(x-1))-10=0



We calculate terms in parentheses: -(7(x-1)), so:

7(x-1)

We multiply parentheses

7x-7

Back to the equation:

-(7x-7)



We get rid of parentheses

15x-7x+7-10=0

We add all the numbers together, and all the variables

8x-3=0

We move all terms containing x to the left, all other terms to the right

8x=3

x=3/8

x=3/8

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