5(3x-2)=y-10(x+1)

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Solution for 5(3x-2)=y-10(x+1) equation:


Simplifying
5(3x + -2) = y + -10(x + 1)

Reorder the terms:
5(-2 + 3x) = y + -10(x + 1)
(-2 * 5 + 3x * 5) = y + -10(x + 1)
(-10 + 15x) = y + -10(x + 1)

Reorder the terms:
-10 + 15x = y + -10(1 + x)
-10 + 15x = y + (1 * -10 + x * -10)
-10 + 15x = y + (-10 + -10x)

Reorder the terms:
-10 + 15x = -10 + -10x + y

Add '10' to each side of the equation.
-10 + 10 + 15x = -10 + -10x + 10 + y

Combine like terms: -10 + 10 = 0
0 + 15x = -10 + -10x + 10 + y
15x = -10 + -10x + 10 + y

Reorder the terms:
15x = -10 + 10 + -10x + y

Combine like terms: -10 + 10 = 0
15x = 0 + -10x + y
15x = -10x + y

Solving
15x = -10x + y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10x' to each side of the equation.
15x + 10x = -10x + 10x + y

Combine like terms: 15x + 10x = 25x
25x = -10x + 10x + y

Combine like terms: -10x + 10x = 0
25x = 0 + y
25x = y

Divide each side by '25'.
x = 0.04y

Simplifying
x = 0.04y

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