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5(3x-3)-2=5(x-5)+58
We move all terms to the left:
5(3x-3)-2-(5(x-5)+58)=0
We multiply parentheses
15x-(5(x-5)+58)-15-2=0
We calculate terms in parentheses: -(5(x-5)+58), so:We add all the numbers together, and all the variables
5(x-5)+58
We multiply parentheses
5x-25+58
We add all the numbers together, and all the variables
5x+33
Back to the equation:
-(5x+33)
15x-(5x+33)-17=0
We get rid of parentheses
15x-5x-33-17=0
We add all the numbers together, and all the variables
10x-50=0
We move all terms containing x to the left, all other terms to the right
10x=50
x=50/10
x=5
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