5(3x-3)-4(2x-5)=3(2x+2)-5

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Solution for 5(3x-3)-4(2x-5)=3(2x+2)-5 equation: 



5(3x-3)-4(2x-5)=3(2x+2)-5

We move all terms to the left:

5(3x-3)-4(2x-5)-(3(2x+2)-5)=0

We multiply parentheses

15x-8x-(3(2x+2)-5)-15+20=0



We calculate terms in parentheses: -(3(2x+2)-5), so:

3(2x+2)-5

We multiply parentheses

6x+6-5

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We add all the numbers together, and all the variables

7x-(6x+1)+5=0

We get rid of parentheses

7x-6x-1+5=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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