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5(3x-3)=2(6+3x)
We move all terms to the left:
5(3x-3)-(2(6+3x))=0
We add all the numbers together, and all the variables
5(3x-3)-(2(3x+6))=0
We multiply parentheses
15x-(2(3x+6))-15=0
We calculate terms in parentheses: -(2(3x+6)), so:We get rid of parentheses
2(3x+6)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
15x-6x-12-15=0
We add all the numbers together, and all the variables
9x-27=0
We move all terms containing x to the left, all other terms to the right
9x=27
x=27/9
x=3
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