5(3x-4)=(2x+7+4x)

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Solution for 5(3x-4)=(2x+7+4x) equation:



5(3x-4)=(2x+7+4x)
We move all terms to the left:
5(3x-4)-((2x+7+4x))=0
We add all the numbers together, and all the variables
5(3x-4)-((6x+7))=0
We multiply parentheses
15x-((6x+7))-20=0
We calculate terms in parentheses: -((6x+7)), so:
(6x+7)
We get rid of parentheses
6x+7
Back to the equation:
-(6x+7)
We get rid of parentheses
15x-6x-7-20=0
We add all the numbers together, and all the variables
9x-27=0
We move all terms containing x to the left, all other terms to the right
9x=27
x=27/9
x=3

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