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5(3x-4)=5(2x+5)
We move all terms to the left:
5(3x-4)-(5(2x+5))=0
We multiply parentheses
15x-(5(2x+5))-20=0
We calculate terms in parentheses: -(5(2x+5)), so:We get rid of parentheses
5(2x+5)
We multiply parentheses
10x+25
Back to the equation:
-(10x+25)
15x-10x-25-20=0
We add all the numbers together, and all the variables
5x-45=0
We move all terms containing x to the left, all other terms to the right
5x=45
x=45/5
x=9
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