5(3x-4)=7(6x+3)-11

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Solution for 5(3x-4)=7(6x+3)-11 equation: 



5(3x-4)=7(6x+3)-11

We move all terms to the left:

5(3x-4)-(7(6x+3)-11)=0

We multiply parentheses

15x-(7(6x+3)-11)-20=0



We calculate terms in parentheses: -(7(6x+3)-11), so:

7(6x+3)-11

We multiply parentheses

42x+21-11

We add all the numbers together, and all the variables

42x+10

Back to the equation:

-(42x+10)



We get rid of parentheses

15x-42x-10-20=0

We add all the numbers together, and all the variables

-27x-30=0

We move all terms containing x to the left, all other terms to the right

-27x=30

x=30/-27

x=-1+1/9

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