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5(3x-5)+10=x-1
We move all terms to the left:
5(3x-5)+10-(x-1)=0
We multiply parentheses
15x-(x-1)-25+10=0
We get rid of parentheses
15x-x+1-25+10=0
We add all the numbers together, and all the variables
14x-14=0
We move all terms containing x to the left, all other terms to the right
14x=14
x=14/14
x=1
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