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5(3x-5)-4=4-5(x-3)
We move all terms to the left:
5(3x-5)-4-(4-5(x-3))=0
We multiply parentheses
15x-(4-5(x-3))-25-4=0
We calculate terms in parentheses: -(4-5(x-3)), so:We add all the numbers together, and all the variables
4-5(x-3)
determiningTheFunctionDomain -5(x-3)+4
We multiply parentheses
-5x+15+4
We add all the numbers together, and all the variables
-5x+19
Back to the equation:
-(-5x+19)
15x-(-5x+19)-29=0
We get rid of parentheses
15x+5x-19-29=0
We add all the numbers together, and all the variables
20x-48=0
We move all terms containing x to the left, all other terms to the right
20x=48
x=48/20
x=2+2/5
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