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5(3x-6)-2=5(x-3)+43
We move all terms to the left:
5(3x-6)-2-(5(x-3)+43)=0
We multiply parentheses
15x-(5(x-3)+43)-30-2=0
We calculate terms in parentheses: -(5(x-3)+43), so:We add all the numbers together, and all the variables
5(x-3)+43
We multiply parentheses
5x-15+43
We add all the numbers together, and all the variables
5x+28
Back to the equation:
-(5x+28)
15x-(5x+28)-32=0
We get rid of parentheses
15x-5x-28-32=0
We add all the numbers together, and all the variables
10x-60=0
We move all terms containing x to the left, all other terms to the right
10x=60
x=60/10
x=6
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