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5(3x-6)-4=5(x-2)+66
We move all terms to the left:
5(3x-6)-4-(5(x-2)+66)=0
We multiply parentheses
15x-(5(x-2)+66)-30-4=0
We calculate terms in parentheses: -(5(x-2)+66), so:We add all the numbers together, and all the variables
5(x-2)+66
We multiply parentheses
5x-10+66
We add all the numbers together, and all the variables
5x+56
Back to the equation:
-(5x+56)
15x-(5x+56)-34=0
We get rid of parentheses
15x-5x-56-34=0
We add all the numbers together, and all the variables
10x-90=0
We move all terms containing x to the left, all other terms to the right
10x=90
x=90/10
x=9
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