5(3x-6)=6(2x-4)-18

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Solution for 5(3x-6)=6(2x-4)-18 equation:



5(3x-6)=6(2x-4)-18
We move all terms to the left:
5(3x-6)-(6(2x-4)-18)=0
We multiply parentheses
15x-(6(2x-4)-18)-30=0
We calculate terms in parentheses: -(6(2x-4)-18), so:
6(2x-4)-18
We multiply parentheses
12x-24-18
We add all the numbers together, and all the variables
12x-42
Back to the equation:
-(12x-42)
We get rid of parentheses
15x-12x+42-30=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4

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