5(3x-7)+8(9-2x)=3(15-4x)

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Solution for 5(3x-7)+8(9-2x)=3(15-4x) equation: 



5(3x-7)+8(9-2x)=3(15-4x)

We move all terms to the left:

5(3x-7)+8(9-2x)-(3(15-4x))=0

We add all the numbers together, and all the variables

5(3x-7)+8(-2x+9)-(3(-4x+15))=0

We multiply parentheses

15x-16x-(3(-4x+15))-35+72=0



We calculate terms in parentheses: -(3(-4x+15)), so:

3(-4x+15)

We multiply parentheses

-12x+45

Back to the equation:

-(-12x+45)



We add all the numbers together, and all the variables

-1x-(-12x+45)+37=0

We get rid of parentheses

-1x+12x-45+37=0

We add all the numbers together, and all the variables

11x-8=0

We move all terms containing x to the left, all other terms to the right

11x=8

x=8/11

x=8/11

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