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5(3x-7)+x=3(x-3)
We move all terms to the left:
5(3x-7)+x-(3(x-3))=0
We add all the numbers together, and all the variables
x+5(3x-7)-(3(x-3))=0
We multiply parentheses
x+15x-(3(x-3))-35=0
We calculate terms in parentheses: -(3(x-3)), so:We add all the numbers together, and all the variables
3(x-3)
We multiply parentheses
3x-9
Back to the equation:
-(3x-9)
16x-(3x-9)-35=0
We get rid of parentheses
16x-3x+9-35=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2
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