5(3x-7)-4=5(x-4)+31

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Solution for 5(3x-7)-4=5(x-4)+31 equation: 



5(3x-7)-4=5(x-4)+31

We move all terms to the left:

5(3x-7)-4-(5(x-4)+31)=0

We multiply parentheses

15x-(5(x-4)+31)-35-4=0



We calculate terms in parentheses: -(5(x-4)+31), so:

5(x-4)+31

We multiply parentheses

5x-20+31

We add all the numbers together, and all the variables

5x+11

Back to the equation:

-(5x+11)



We add all the numbers together, and all the variables

15x-(5x+11)-39=0

We get rid of parentheses

15x-5x-11-39=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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