5(3x-7)=20-2(x+1)

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Solution for 5(3x-7)=20-2(x+1) equation: 



5(3x-7)=20-2(x+1)

We move all terms to the left:

5(3x-7)-(20-2(x+1))=0

We multiply parentheses

15x-(20-2(x+1))-35=0



We calculate terms in parentheses: -(20-2(x+1)), so:

20-2(x+1)

determiningTheFunctionDomain
-2(x+1)+20

We multiply parentheses

-2x-2+20

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)



We get rid of parentheses

15x+2x-18-35=0

We add all the numbers together, and all the variables

17x-53=0

We move all terms containing x to the left, all other terms to the right

17x=53

x=53/17

x=3+2/17

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