5(3x-8)+11=2-2x+3(x-4)

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Solution for 5(3x-8)+11=2-2x+3(x-4) equation: 



5(3x-8)+11=2-2x+3(x-4)

We move all terms to the left:

5(3x-8)+11-(2-2x+3(x-4))=0

We multiply parentheses

15x-(2-2x+3(x-4))-40+11=0



We calculate terms in parentheses: -(2-2x+3(x-4)), so:

2-2x+3(x-4)

determiningTheFunctionDomain
-2x+3(x-4)+2

We multiply parentheses

-2x+3x-12+2

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)



We add all the numbers together, and all the variables

15x-(x-10)-29=0

We get rid of parentheses

15x-x+10-29=0

We add all the numbers together, and all the variables

14x-19=0

We move all terms containing x to the left, all other terms to the right

14x=19

x=19/14

x=1+5/14

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