5(3x-9)-8=5(x-4)+27

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Solution for 5(3x-9)-8=5(x-4)+27 equation:



5(3x-9)-8=5(x-4)+27
We move all terms to the left:
5(3x-9)-8-(5(x-4)+27)=0
We multiply parentheses
15x-(5(x-4)+27)-45-8=0
We calculate terms in parentheses: -(5(x-4)+27), so:
5(x-4)+27
We multiply parentheses
5x-20+27
We add all the numbers together, and all the variables
5x+7
Back to the equation:
-(5x+7)
We add all the numbers together, and all the variables
15x-(5x+7)-53=0
We get rid of parentheses
15x-5x-7-53=0
We add all the numbers together, and all the variables
10x-60=0
We move all terms containing x to the left, all other terms to the right
10x=60
x=60/10
x=6

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