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5(3x-9)=7(2x-3)+5
We move all terms to the left:
5(3x-9)-(7(2x-3)+5)=0
We multiply parentheses
15x-(7(2x-3)+5)-45=0
We calculate terms in parentheses: -(7(2x-3)+5), so:We get rid of parentheses
7(2x-3)+5
We multiply parentheses
14x-21+5
We add all the numbers together, and all the variables
14x-16
Back to the equation:
-(14x-16)
15x-14x+16-45=0
We add all the numbers together, and all the variables
x-29=0
We move all terms containing x to the left, all other terms to the right
x=29
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