5(3x2)=5

Solution for 5(3x2)=5 equation:

5(3x^2)=5

We move all terms to the left:

5(3x^2)-(5)=0

a = 53; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·53·(-5)
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{265}}{2*53}=\frac{0-2\sqrt{265}}{106}
=-\frac{2\sqrt{265}}{106}
=-\frac{\sqrt{265}}{53}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{265}}{2*53}=\frac{0+2\sqrt{265}}{106}
=\frac{2\sqrt{265}}{106}
=\frac{\sqrt{265}}{53}
$