5(3y+12)=(5y+20)

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Solution for 5(3y+12)=(5y+20) equation: 



5(3y+12)=(5y+20)

We move all terms to the left:

5(3y+12)-((5y+20))=0

We multiply parentheses

15y-((5y+20))+60=0



We calculate terms in parentheses: -((5y+20)), so:

(5y+20)

We get rid of parentheses

5y+20

Back to the equation:

-(5y+20)



We get rid of parentheses

15y-5y-20+60=0

We add all the numbers together, and all the variables

10y+40=0

We move all terms containing y to the left, all other terms to the right

10y=-40

y=-40/10

y=-4

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