5(3y+12)=6(3y+20)

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Solution for 5(3y+12)=6(3y+20) equation: 



5(3y+12)=6(3y+20)

We move all terms to the left:

5(3y+12)-(6(3y+20))=0

We multiply parentheses

15y-(6(3y+20))+60=0



We calculate terms in parentheses: -(6(3y+20)), so:

6(3y+20)

We multiply parentheses

18y+120

Back to the equation:

-(18y+120)



We get rid of parentheses

15y-18y-120+60=0

We add all the numbers together, and all the variables

-3y-60=0

We move all terms containing y to the left, all other terms to the right

-3y=60

y=60/-3

y=-20

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