5(3y+12)=6(5+y+20)

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Solution for 5(3y+12)=6(5+y+20) equation: 



5(3y+12)=6(5+y+20)

We move all terms to the left:

5(3y+12)-(6(5+y+20))=0

We add all the numbers together, and all the variables

5(3y+12)-(6(y+25))=0

We multiply parentheses

15y-(6(y+25))+60=0



We calculate terms in parentheses: -(6(y+25)), so:

6(y+25)

We multiply parentheses

6y+150

Back to the equation:

-(6y+150)



We get rid of parentheses

15y-6y-150+60=0

We add all the numbers together, and all the variables

9y-90=0

We move all terms containing y to the left, all other terms to the right

9y=90

y=90/9

y=10

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