5(3y+2)+10=100

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Solution for 5(3y+2)+10=100 equation: 



5(3y+2)+10=100

We move all terms to the left:

5(3y+2)+10-(100)=0

We add all the numbers together, and all the variables

5(3y+2)-90=0

We multiply parentheses

15y+10-90=0

We add all the numbers together, and all the variables

15y-80=0

We move all terms containing y to the left, all other terms to the right

15y=80

y=80/15

y=5+1/3

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