5(3y+5)+11=6(2y+1)-2

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Solution for 5(3y+5)+11=6(2y+1)-2 equation: 



5(3y+5)+11=6(2y+1)-2

We move all terms to the left:

5(3y+5)+11-(6(2y+1)-2)=0

We multiply parentheses

15y-(6(2y+1)-2)+25+11=0



We calculate terms in parentheses: -(6(2y+1)-2), so:

6(2y+1)-2

We multiply parentheses

12y+6-2

We add all the numbers together, and all the variables

12y+4

Back to the equation:

-(12y+4)



We add all the numbers together, and all the variables

15y-(12y+4)+36=0

We get rid of parentheses

15y-12y-4+36=0

We add all the numbers together, and all the variables

3y+32=0

We move all terms containing y to the left, all other terms to the right

3y=-32

y=-32/3

y=-10+2/3

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