5(3y-12)+4y=35

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Solution for 5(3y-12)+4y=35 equation:



5(3y-12)+4y=35
We move all terms to the left:
5(3y-12)+4y-(35)=0
We add all the numbers together, and all the variables
4y+5(3y-12)-35=0
We multiply parentheses
4y+15y-60-35=0
We add all the numbers together, and all the variables
19y-95=0
We move all terms containing y to the left, all other terms to the right
19y=95
y=95/19
y=5

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