5(3y-12)+4y=35

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Solution for 5(3y-12)+4y=35 equation: 



5(3y-12)+4y=35

We move all terms to the left:

5(3y-12)+4y-(35)=0

We add all the numbers together, and all the variables

4y+5(3y-12)-35=0

We multiply parentheses

4y+15y-60-35=0

We add all the numbers together, and all the variables

19y-95=0

We move all terms containing y to the left, all other terms to the right

19y=95

y=95/19

y=5

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