5(3y-2(2y+5))+y+28=0

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Solution for 5(3y-2(2y+5))+y+28=0 equation: 



5(3y-2(2y+5))+y+28=0

We add all the numbers together, and all the variables

y+5(3y-2(2y+5))+28=0

We move all terms containing y to the left, all other terms to the right

y+5(3y-2(2y+5))=-28

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