5(3y-2)+2y=10

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Solution for 5(3y-2)+2y=10 equation: 



5(3y-2)+2y=10

We move all terms to the left:

5(3y-2)+2y-(10)=0

We add all the numbers together, and all the variables

2y+5(3y-2)-10=0

We multiply parentheses

2y+15y-10-10=0

We add all the numbers together, and all the variables

17y-20=0

We move all terms containing y to the left, all other terms to the right

17y=20

y=20/17

y=1+3/17

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