5(3y-2)-2(y+1)=27

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Solution for 5(3y-2)-2(y+1)=27 equation: 



5(3y-2)-2(y+1)=27

We move all terms to the left:

5(3y-2)-2(y+1)-(27)=0

We multiply parentheses

15y-2y-10-2-27=0

We add all the numbers together, and all the variables

13y-39=0

We move all terms containing y to the left, all other terms to the right

13y=39

y=39/13

y=3

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