5(3y-2)=10y

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Solution for 5(3y-2)=10y equation:



5(3y-2)=10y
We move all terms to the left:
5(3y-2)-(10y)=0
We add all the numbers together, and all the variables
-10y+5(3y-2)=0
We multiply parentheses
-10y+15y-10=0
We add all the numbers together, and all the variables
5y-10=0
We move all terms containing y to the left, all other terms to the right
5y=10
y=10/5
y=2

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