5(3y-2)=10y

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Solution for 5(3y-2)=10y equation: 



5(3y-2)=10y

We move all terms to the left:

5(3y-2)-(10y)=0

We add all the numbers together, and all the variables

-10y+5(3y-2)=0

We multiply parentheses

-10y+15y-10=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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