5(3y-4)+4=6(6y+2)-16

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Solution for 5(3y-4)+4=6(6y+2)-16 equation: 



5(3y-4)+4=6(6y+2)-16

We move all terms to the left:

5(3y-4)+4-(6(6y+2)-16)=0

We multiply parentheses

15y-(6(6y+2)-16)-20+4=0



We calculate terms in parentheses: -(6(6y+2)-16), so:

6(6y+2)-16

We multiply parentheses

36y+12-16

We add all the numbers together, and all the variables

36y-4

Back to the equation:

-(36y-4)



We add all the numbers together, and all the variables

15y-(36y-4)-16=0

We get rid of parentheses

15y-36y+4-16=0

We add all the numbers together, and all the variables

-21y-12=0

We move all terms containing y to the left, all other terms to the right

-21y=12

y=12/-21

y=-4/7

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