5(3y-4)+8-7y=2(3y+9)+y+14

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Solution for 5(3y-4)+8-7y=2(3y+9)+y+14 equation: 



5(3y-4)+8-7y=2(3y+9)+y+14

We move all terms to the left:

5(3y-4)+8-7y-(2(3y+9)+y+14)=0

We add all the numbers together, and all the variables

-7y+5(3y-4)-(2(3y+9)+y+14)+8=0

We multiply parentheses

-7y+15y-(2(3y+9)+y+14)-20+8=0



We calculate terms in parentheses: -(2(3y+9)+y+14), so:

2(3y+9)+y+14

We add all the numbers together, and all the variables

y+2(3y+9)+14

We multiply parentheses

y+6y+18+14

We add all the numbers together, and all the variables

7y+32

Back to the equation:

-(7y+32)



We add all the numbers together, and all the variables

8y-(7y+32)-12=0

We get rid of parentheses

8y-7y-32-12=0

We add all the numbers together, and all the variables

y-44=0

We move all terms containing y to the left, all other terms to the right

y=44

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