5(3y-4)+8-7y=2(3y+9)=y=14

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Solution for 5(3y-4)+8-7y=2(3y+9)=y=14 equation: 



5(3y-4)+8-7y=2(3y+9)=y=14

We move all terms to the left:

5(3y-4)+8-7y-(2(3y+9))=0

We add all the numbers together, and all the variables

-7y+5(3y-4)-(2(3y+9))+8=0

We multiply parentheses

-7y+15y-(2(3y+9))-20+8=0



We calculate terms in parentheses: -(2(3y+9)), so:

2(3y+9)

We multiply parentheses

6y+18

Back to the equation:

-(6y+18)



We add all the numbers together, and all the variables

8y-(6y+18)-12=0

We get rid of parentheses

8y-6y-18-12=0

We add all the numbers together, and all the variables

2y-30=0

We move all terms containing y to the left, all other terms to the right

2y=30

y=30/2

y=15

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