5(3y-4)/2=7

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Solution for 5(3y-4)/2=7 equation: 


y in (-oo:+oo)

(5*(3*y-4))/2 = 7 // - 7

(5*(3*y-4))/2-7 = 0

(5*(3*y-4))/2+(-7*2)/2 = 0

5*(3*y-4)-7*2 = 0

15*y-34 = 0

(15*y-34)/2 = 0

(15*y-34)/2 = 0 // * 2

15*y-34 = 0

15*y-34 = 0 // + 34

15*y = 34 // : 15

y = 34/15

y = 34/15

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