5(3y-4)/2y=7

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Solution for 5(3y-4)/2y=7 equation: 


y in (-oo:+oo)

y*((5*(3*y-4))/2) = 7 // - 7

y*((5*(3*y-4))/2)-7 = 0

(5*y*(3*y-4))/2-7 = 0

(5*y*(3*y-4))/2+(-7*2)/2 = 0

5*y*(3*y-4)-7*2 = 0

15*y^2-20*y-14 = 0

15*y^2-20*y-14 = 0

15*y^2-20*y-14 = 0

DELTA = (-20)^2-(-14*4*15)

DELTA = 1240

DELTA > 0

y = (1240^(1/2)+20)/(2*15) or y = (20-1240^(1/2))/(2*15)

y = (2*310^(1/2)+20)/30 or y = (20-2*310^(1/2))/30

(y-((20-2*310^(1/2))/30))*(y-((2*310^(1/2)+20)/30)) = 0

((y-((20-2*310^(1/2))/30))*(y-((2*310^(1/2)+20)/30)))/2 = 0

((y-((20-2*310^(1/2))/30))*(y-((2*310^(1/2)+20)/30)))/2 = 0 // * 2

(y-((20-2*310^(1/2))/30))*(y-((2*310^(1/2)+20)/30)) = 0

( y-((2*310^(1/2)+20)/30) )

y-((2*310^(1/2)+20)/30) = 0 // + (2*310^(1/2)+20)/30

y = (2*310^(1/2)+20)/30

( y-((20-2*310^(1/2))/30) )

y-((20-2*310^(1/2))/30) = 0 // + (20-2*310^(1/2))/30

y = (20-2*310^(1/2))/30

y in { (2*310^(1/2)+20)/30, (20-2*310^(1/2))/30 }

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