5(3y-7)+y=3(y-3)

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Solution for 5(3y-7)+y=3(y-3) equation: 



5(3y-7)+y=3(y-3)

We move all terms to the left:

5(3y-7)+y-(3(y-3))=0

We add all the numbers together, and all the variables

y+5(3y-7)-(3(y-3))=0

We multiply parentheses

y+15y-(3(y-3))-35=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

16y-(3y-9)-35=0

We get rid of parentheses

16y-3y+9-35=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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