5(3y-8)-5y=10(y-5)-7

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Solution for 5(3y-8)-5y=10(y-5)-7 equation: 



5(3y-8)-5y=10(y-5)-7

We move all terms to the left:

5(3y-8)-5y-(10(y-5)-7)=0

We add all the numbers together, and all the variables

-5y+5(3y-8)-(10(y-5)-7)=0

We multiply parentheses

-5y+15y-(10(y-5)-7)-40=0



We calculate terms in parentheses: -(10(y-5)-7), so:

10(y-5)-7

We multiply parentheses

10y-50-7

We add all the numbers together, and all the variables

10y-57

Back to the equation:

-(10y-57)



We add all the numbers together, and all the variables

10y-(10y-57)-40=0

We get rid of parentheses

10y-10y+57-40=0

We add all the numbers together, and all the variables

17!=0

There is no solution for this equation

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