5(3z+2)-2=-2(1-7z)

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Solution for 5(3z+2)-2=-2(1-7z) equation: 



5(3z+2)-2=-2(1-7z)

We move all terms to the left:

5(3z+2)-2-(-2(1-7z))=0

We add all the numbers together, and all the variables

5(3z+2)-(-2(-7z+1))-2=0

We multiply parentheses

15z-(-2(-7z+1))+10-2=0



We calculate terms in parentheses: -(-2(-7z+1)), so:

-2(-7z+1)

We multiply parentheses

14z-2

Back to the equation:

-(14z-2)



We add all the numbers together, and all the variables

15z-(14z-2)+8=0

We get rid of parentheses

15z-14z+2+8=0

We add all the numbers together, and all the variables

z+10=0

We move all terms containing z to the left, all other terms to the right

z=-10

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