5(3z+2)-2=-2(1-7z)

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Solution for 5(3z+2)-2=-2(1-7z) equation:



5(3z+2)-2=-2(1-7z)
We move all terms to the left:
5(3z+2)-2-(-2(1-7z))=0
We add all the numbers together, and all the variables
5(3z+2)-(-2(-7z+1))-2=0
We multiply parentheses
15z-(-2(-7z+1))+10-2=0
We calculate terms in parentheses: -(-2(-7z+1)), so:
-2(-7z+1)
We multiply parentheses
14z-2
Back to the equation:
-(14z-2)
We add all the numbers together, and all the variables
15z-(14z-2)+8=0
We get rid of parentheses
15z-14z+2+8=0
We add all the numbers together, and all the variables
z+10=0
We move all terms containing z to the left, all other terms to the right
z=-10

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