5(3z+4)=12-2(z-4)

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Solution for 5(3z+4)=12-2(z-4) equation:


Simplifying
5(3z + 4) = 12 + -2(z + -4)

Reorder the terms:
5(4 + 3z) = 12 + -2(z + -4)
(4 * 5 + 3z * 5) = 12 + -2(z + -4)
(20 + 15z) = 12 + -2(z + -4)

Reorder the terms:
20 + 15z = 12 + -2(-4 + z)
20 + 15z = 12 + (-4 * -2 + z * -2)
20 + 15z = 12 + (8 + -2z)

Combine like terms: 12 + 8 = 20
20 + 15z = 20 + -2z

Add '-20' to each side of the equation.
20 + -20 + 15z = 20 + -20 + -2z

Combine like terms: 20 + -20 = 0
0 + 15z = 20 + -20 + -2z
15z = 20 + -20 + -2z

Combine like terms: 20 + -20 = 0
15z = 0 + -2z
15z = -2z

Solving
15z = -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
15z + 2z = -2z + 2z

Combine like terms: 15z + 2z = 17z
17z = -2z + 2z

Combine like terms: -2z + 2z = 0
17z = 0

Divide each side by '17'.
z = 0

Simplifying
z = 0

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